6 Ivy games to go, 2^6 = 64 possible outcomes. In past years I had enough stamina to compute ILT possibilities in all 64 cases.
With apologies to Big Green fans, as of now I'm only going to do the scenarios where Dartmouth does not get an Ivy win this year, which cuts the number down to 16, and I'm only going to do the simplest tie-breaker of record among the tied teams. Complete list of tie-breakers is here:
https://ivyleague.com/sports/2018/4/17/ ... 80748.aspx
And I'm not sure how (3a) applies in a case like (C,Y,Pr),(B,H,Pe)
C>B,H>Pr,Y>H,Pr>C: (C,Y,Pr),(B,H,Pe)
C>B,H>Pr,Y>H,C>Pr: C,Y,H,Pr
C>B,H>Pr,H>Y,Pr>C: (C,H,Pr),B
C>B,H>Pr,H>Y,C>Pr: C,H,(B,Pr,Y)
C>B,Pr>H,Y>H,Pr>C: Pr,C,Y,B
C>B,Pr>H,Y>H,C>Pr: C,Y,Pr,B
C>B,Pr>H,H>Y,Pr>C: Pr,C,H,B
C>B,Pr>H,H>Y,C>Pr: C,Pr,H,B
B>C,H>Pr,Y>H,Pr>C: (B,Pr,Y),Pe
B>C,H>Pr,Y>H,C>Pr: B,C,Y,(H,Pe,Pr)
B>C,H>Pr,H>Y,Pr>C: H,Pr,B,(C,Pe,Y)
B>C,H>Pr,H>Y,C>Pr: (B,C,H),Y
B>C,Pr>H,Y>H,Pr>C: Pr,B,Y,Pe
B>C,Pr>H,Y>H,C>Pr: B,C,Y,Pr
B>C,Pr>H,H>Y,Pr>C: Pr,B,Pe,C
B>C,Pr>H,H>Y,C>Pr: (B,C,Pr),(H,Pe,Y)